std::chrono::operator+,std::chrono::operator-(std::chrono::day) (3) Linux Manual Page
std::chrono::operator+,std::chrono::operator-(std::chrono::day) – std::chrono::operator+,std::chrono::operator-(std::chrono::day)
Synopsis
constexpr std::chrono::day operator+(const std::chrono::day &d, (1)(since C++ 20)
const std::chrono::days &ds) noexcept;
constexpr std::chrono::day operator+(const std::chrono::days &ds, (2)(since C++ 20)
const std::chrono::day &d) noexcept;
constexpr std::chrono::day operator-(const std::chrono::day &d, (3)(since C++ 20)
const std::chrono::days &ds) noexcept;
constexpr std::chrono::days operator-(const std::chrono::day &x, (4)(since C++ 20)
const std::chrono::day &y) noexcept;
1-2) Adds ds.count() days to d.
3) Subtracts ds.count() days from d.
4) Calculate the difference, in days, between two day x and y.
Return value
1-2) std::chrono::day(unsigned(d) + ds.count())
3) std::chrono::day(unsigned(d) – ds.count())
4) std::chrono::days(int(unsigned(x)) – int(unsigned(y)))
Notes
For (1-3), if the result would be outside the range [0, 255], the actual stored value is unspecified.
Example
This section is incomplete
Reason: no example
See also
operator++ increments or decrements the day
operator++(int) (public member function)
operator--
operator--(int)
adds or subtracts a number of days
operator+= (public member function)
operator-=
