std::forward (3) Linux Manual Page
std::forward – std::forward
Synopsis
Defined in header <utility>
template< class T > (1) (since C++11)
T&& forward( typename std::remove_reference<T>::type& t ) noexcept; (until C++14)
template< class T > (1) (since C++14)
constexpr T&& forward( typename std::remove_reference<T>::type& t ) noexcept;
template< class T > (2) (since C++11)
T&& forward( typename std::remove_reference<T>::type&& t ) noexcept; (until C++14)
template< class T > (2) (since C++14)
constexpr T&& forward( typename std::remove_reference<T>::type&& t ) noexcept;
1) Forwards lvalues as either lvalues or as rvalues, depending on T
When t is a forwarding_reference (a function argument that is declared as an rvalue reference to a cv-unqualified function template parameter), this overload forwards the argument to another function with the value_category it had when passed to the calling function.
For example, if used in wrapper such as the following, the template behaves as described below:
template <class T>
void wrapper(T &&arg)
{
// arg is always lvalue
foo(std::forward<T>(arg)); // Forward as lvalue or as rvalue, depending on T
}
* If a call to wrapper() passes an rvalue std::string, then T is deduced to std::string (not std::string&, const std::string&, or std::string&&), and std::forward ensures that an rvalue reference is passed to foo.
* If a call to wrapper() passes a const lvalue std::string, then T is deduced to const std::string&, and std::forward ensures that a const lvalue reference is passed to foo.
* If a call to wrapper() passes a non-const lvalue std::string, then T is deduced to std::string&, and std::forward ensures that a non-const lvalue reference is passed to foo.
2) Forwards rvalues as rvalues and prohibits forwarding of rvalues as lvalues
This overload makes it possible to forward a result of an expression (such as function call), which may be rvalue or lvalue, as the original value category of a forwarding reference argument.
For example, if a wrapper does not just forward its argument, but calls a member function on the argument, and forwards its result:
// transforming wrapper
template <class T>
void wrapper(T &&arg)
{
foo(forward<decltype(forward<T>(arg).get())>(forward<T>(arg).get()));
}
where the type of arg may be
struct Arg
{
int i = 1;
int get() &&
{
return i;
} // call to this overload is rvalue
int &get() &
{
return i;
} // call to this overload is lvalue
};
Attempting to forward an rvalue as an lvalue, such as by instantiating the form (2) with lvalue reference type T, is a compile-time error.
Notes
See template_argument_deduction for the special rules behind forwarding references (T&& used as a function parameter) and forwarding_references for other detail.
Parameters
t – the object to be forwarded
Return value
static_cast<T&&>(t)
Example
This example demonstrates perfect forwarding of the parameter(s) to the argument of the constructor of class T. Also, perfect forwarding of parameter packs is demonstrated.
// Run this code
#include <iostream>
#include <memory>
#include <utility>
struct A {
A(int &&n)
{
std::cout << "rvalue overload, n=" << n << "\n";
}
A(int &n)
{
std::cout << "lvalue overload, n=" << n << "\n";
}
};
class B
{
public:
template <class T1, class T2, class T3>
B(T1 &&t1, T2 &&t2, T3 &&t3)
: a1_{std::forward<T1>(t1)},
a2_{std::forward<T2>(t2)},
a3_{std::forward<T3>(t3)}
{
}
private:
A a1_, a2_, a3_;
};
template <class T, class U>
std::unique_ptr<T> make_unique1(U &&u)
{
return std::unique_ptr<T>(new T(std::forward<U>(u)));
}
template <class T, class... U>
std::unique_ptr<T> make_unique2(U &&...u)
{
return std::unique_ptr<T>(new T(std::forward<U>(u)...));
}
int main()
{
auto p1 = make_unique1<A>(2); // rvalue
int i = 1;
auto p2 = make_unique1<A>(i); // lvalue
std::cout << "B\n";
auto t = make_unique2<B>(2, i, 3);
}
Output:
Complexity
Constant
See also
move obtains an rvalue reference
(C++11)
move_if_noexcept obtains an rvalue reference if the move constructor does not throw
(C++11)
