std::is_bind_expression (3) Linux Manual Page
std::is_bind_expression – std::is_bind_expression
Synopsis
Defined in header<functional>
template <class T>
(since C++ 11)
struct is_bind_expression;
If T is the type produced by a call to std::bind, this template is derived from std::true_type. For any other type, this template is derived from std::false_type.
This template may be specialized for a user-defined type T to implement UnaryTypeTrait with BaseCharacteristic of std::true_type to indicate that T should be treated by std::bind as if it were the type of a bind subexpression: when a bind-generated function object is invoked, a bound argument of this type will be invoked as a function object and will be given all the unbound arguments passed to the bind-generated object.
Helper variable template
template< class T > (since C++17)
inline constexpr bool is_bind_expression_v = is_bind_expression<T>::value;
Inherited from std::integral_constant
Member constants
value true if T is a function object generated by std::bind, false otherwise
[static]
Member functions
operator bool (public member function)
operator() returns value
(C++14)
Member types
Type Definition
value_type bool
type std::integral_constant<bool, value>
Example
// Run this code
#include <iostream>
#include <type_traits>
#include <functional>
struct MyBind {
typedef int result_type;
int operator()(int a, int b) const
{
return a + b;
}
};
namespace std
{
template <>
struct is_bind_expression<MyBind> : public true_type {
};
} // namespace std
int f(int n1, int n2)
{
return n1 + n2;
}
int main()
{
// as if bind(f, bind(MyBind(), _1, _2), 2)
auto b = std::bind(f, MyBind(), 2);
std::cout << "Adding 2 to the sum of 10 and 11 gives " << b(10, 11) << '\n';
}
Output:
See also
bind binds one or more arguments to a function object
(C++11)
