std::is_move_assignable,std::is_trivially_move_assignable,std::is_nothrow_move_assignable (3) Linux Manual Page
std::is_move_assignable,std::is_trivially_move_assignable,std::is_nothrow_move_assignable – std::is_move_assignable,std::is_trivially_move_assignable,std::is_nothrow_move_assignable
Synopsis
Defined in header<type_traits>
template <class T>
(1)(since C++ 11)
struct is_move_assignable;
template <class T>
(2)(since C++ 11)
struct is_trivially_move_assignable;
template <class T>
(3)(since C++ 11)
struct is_nothrow_move_assignable;
1) If T is not a referenceable type (i.e., possibly cv-qualified void or a function type with a cv-qualifier-seq or a ref-qualifier), provides a member constant value equal to false. Otherwise, provides a member constant value equal to std::is_assignable<T&, T&&>::value.
2) Same as 1), but uses std::is_trivially_assignable<T&, T&&>
3) Same as 1), but uses std::is_nothrow_assignable<T&, T&&>
T shall be a complete type, (possibly cv-qualified) void, or an array of unknown bound. Otherwise, the behavior is undefined.
If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.
Helper variable templates
template< class T > (since C++17)
inline constexpr bool is_move_assignable_v = is_move_assignable<T>::value;
template< class T > (since C++17)
inline constexpr bool is_trivially_move_assignable_v = is_trivially_move_assignable<T>::value;
template< class T > (since C++17)
inline constexpr bool is_nothrow_move_assignable_v = is_nothrow_move_assignable<T>::value;
Inherited from std::integral_constant
Member constants
value true if T is move-assignable, false otherwise
[static]
Member functions
operator bool (public member function)
operator() returns value
(C++14)
Member types
Type Definition
value_type bool
type std::integral_constant<bool, value>
Possible implementation
Notes
The trait std::is_move_assignable is less strict than MoveAssignable because it does not check the type of the result of the assignment (which, for a MoveAssignable type, must be T&), nor the semantic requirement that the target’s value after the assignment is equivalent to the source’s value before the assignment.
The type does not have to implement a move_assignment_operator in order to satisfy this trait; see MoveAssignable for details.
Example
// Run this code
#include <iostream>
#include <string>
#include <type_traits>
struct Foo {
int n;
};
struct NoMove {
// prevents implicit declaration of default move assignment operator
// however, the class is still move-assignable because its
// copy assignment operator can bind to an rvalue argument
NoMove &operator=(const NoMove &)
{
return *this;
}
};
int main()
{
std::cout << std::boolalpha
<< "std::string is nothrow move-assignable? "
<< std::is_nothrow_move_assignable<std::string>::value << '\n'
<< "int[2] is move-assignable? "
<< std::is_move_assignable<int[2]>::value << '\n'
<< "Foo is trivally move-assignable? "
<< std::is_trivially_move_assignable<Foo>::value << '\n';
std::cout << std::boolalpha
<< "NoMove is move-assignable? "
<< std::is_move_assignable<NoMove>::value << '\n'
<< "NoMove is nothrow move-assignable? "
<< std::is_nothrow_move_assignable<NoMove>::value << '\n';
}
Output:
See also
is_assignable
is_trivially_assignable
is_nothrow_assignable checks if a type has a assignment operator for a specific argument
(C++11)
(C++11)
(C++11)
is_copy_assignable
is_trivially_copy_assignable
is_nothrow_copy_assignable checks if a type has a copy assignment operator
(C++11)
(C++11)
(C++11)
