std::numeric_limits::denorm_min (3) Linux Manual Page
std::numeric_limits<T>::denorm_min – std::numeric_limits<T>::denorm_min
Synopsis
static T denorm_min() throw(); (until C++11)
static constexpr T denorm_min() noexcept; (since C++11)
Returns the minimum positive subnormal_value of the type T, if std::numeric_limits<T>::has_denorm != std::denorm_absent, otherwise returns std::numeric_limits<T>::min(). Only meaningful for floating-point types.
Return value
T std::numeric_limits<T>::denorm_min()
/* non-specialized */ T()
bool false
char 0
signed char 0
unsigned char 0
wchar_t 0
char8_t 0
char16_t 0
char32_t 0
short 0
unsigned short 0
int 0
unsigned int 0
long 0
unsigned long 0
long long 0
unsigned long long 0
float 2-149
double 2-1074
long double /* implementation-defined */
Example
Demonstates the underlying bit structure of the denorm_min() and prints the values
// Run this code
#include <cassert>
#include <cstdint>
#include <cstring>
#include <iostream>
#include <limits>
int main()
{
// the smallest subnormal value has sign bit = 0, exponent = 0
// and only the least significant bit of the fraction is 1
std::uint32_t denorm_bits = 0x0001;
float denorm_float;
std::memcpy(&denorm_float, &denorm_bits, sizeof(float));
assert(denorm_float == std::numeric_limits<float>::denorm_min());
std::cout << "float\tmin()\t\tdenorm_min()\n";
std::cout << "\t" << std::numeric_limits<float>::min() << '\t';
std::cout << std::numeric_limits<float>::denorm_min() << '\n';
std::cout << "double\tmin()\t\tdenorm_min()\n";
std::cout << "\t" << std::numeric_limits<double>::min() << '\t';
std::cout << std::numeric_limits<double>::denorm_min() << '\n';
}
Possible output:
See also
min returns the smallest finite value of the given type
[static]
has_denorm identifies the denormalization style used by the floating-point type
[static]
lowest returns the lowest finite value of the given type
[static] (C++11)
