std::_Exit (3) - Linux Manuals

std::_Exit: std::_Exit

NAME

std::_Exit - std::_Exit

Synopsis

Defined in header <cstdlib>
[[noreturn]] void _Exit( int exit_code ) noexcept; (since C++11)

Causes normal program termination to occur without completely cleaning the resources.
Destructors of variables with automatic, thread local and static storage durations are not called. Functions passed to std::at_quick_exit() or std::atexit() are not called. Whether open resources such as files are closed is implementation defined.
If exit_code is 0 or EXIT_SUCCESS, an implementation-defined status indicating successful termination is returned to the host environment. If exit_code is EXIT_FAILURE, an implementation-defined status, indicating unsuccessful termination, is returned. In other cases implementation-defined status value is returned.

Parameters

exit_code - exit status of the program

Return value

(none)

Example

// Run this code

  #include <iostream>

  class Static {
  public:
      ~Static()
      {
          std::cout << "Static dtor\n";
      }
  };

  class Local {
  public:
      ~Local()
      {
          std::cout << "Local dtor\n";
      }
  };

  Static static_variable; // dtor of this object will *not* be called

  void atexit_handler()
  {
      std::cout << "atexit handler\n";
  }

  int main()
  {
      Local local_variable; // dtor of this object will *not* be called

      // handler will *not* be called
      const int result = std::atexit(atexit_handler);

      if (result != 0) {
          std::cerr << "atexit registration failed\n";
          return EXIT_FAILURE;
      }

      std::cout << "test" << std::endl; // flush from std::endl
          // needs to be here, otherwise nothing will be printed
      std::_Exit(EXIT_FAILURE);
  }

Output:

  test