std::chrono::operator==,!=,<,<=,>,>=(std::chrono::year_month_day_last) (3) - Linux Manuals

std::chrono::operator==,!=,<,<=,>,>=(std::chrono::year_month_day_last): std::chrono::operator==,!=,<,<=,>,>=(std::chrono::year_month_day_last)

NAME

std::chrono::operator==,!=,<,<=,>,>=(std::chrono::year_month_day_last) - std::chrono::operator==,!=,<,<=,>,>=(std::chrono::year_month_day_last)

Synopsis

constexpr bool operator==(const std::chrono::year_month_day_last& x, (1) (since C++20)
const std::chrono::year_month_day_last& y) noexcept;
constexpr bool operator!=(const std::chrono::year_month_day_last& x, (2) (since C++20)
const std::chrono::year_month_day_last& y) noexcept;
constexpr bool operator< (const std::chrono::year_month_day_last& x, (3) (since C++20)
const std::chrono::year_month_day_last& y) noexcept;
constexpr bool operator> (const std::chrono::year_month_day_last& x, (4) (since C++20)
const std::chrono::year_month_day_last& y) noexcept;
constexpr bool operator<=(const std::chrono::year_month_day_last& x, (5) (since C++20)
const std::chrono::year_month_day_last& y) noexcept;
constexpr bool operator>=(const std::chrono::year_month_day_last& x, (6) (since C++20)
const std::chrono::year_month_day_last& y) noexcept;

Compares the two year_month_day_last objects x and y. This is a lexicographical comparison: the year() is compared first, then month().

Return value

1) x.year() == y.year() && x.month() == y.month()
2) !(x == y)
3) If x.year() != y.year(), x.year() < y.year(); otherwise, x.month() < y.month().
4) y < x
5) !(y < x)
6) !(x < y)

Notes

If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.