std::chrono::weekday::operator+=,std::chrono::weekday::operator-= (3) - Linux Man Pages

std::chrono::weekday::operator+=,std::chrono::weekday::operator-=: std::chrono::weekday::operator+=,std::chrono::weekday::operator-=

NAME

std::chrono::weekday::operator+=,std::chrono::weekday::operator-= - std::chrono::weekday::operator+=,std::chrono::weekday::operator-=

Synopsis


constexpr std::chrono::weekday& operator+=(const std::chrono::days& d) noexcept; (1) (since C++20)
constexpr std::chrono::weekday& operator-=(const std::chrono::days& d) noexcept; (2) (since C++20)


Adds or subtracts d.count() from the weekday value, reducing the result modulo 7 to an integer in the range [0, 6].
1) Performs *this = *this + d;
2) Performs *this = *this - d;

Return value


A reference to this weekday after modification.

Notes


After a call to one of these functions, ok() is always true if no overflow occurred during the operation.

Example


 This section is incomplete
 Reason: no example

See also


operator++ increments or decrements the weekday
operator++(int) (public member function)
operator--
operator--(int)
                performs arithmetic on weekdays
operator+ (function)
operator-