std::experimental::propagate_const<T>::operator= (3) - Linux Man Pages

std::experimental::propagate_const<T>::operator=: std::experimental::propagate_const<T>::operator=

NAME

std::experimental::propagate_const<T>::operator= - std::experimental::propagate_const<T>::operator=

Synopsis


constexpr propagate_const& operator=( propagate_const&& p ) = default; (1) (library fundamentals TS v2)
template<class U> (2) (library fundamentals TS v2)
constexpr propagate_const& operator=( propagate_const<U>&& pu );
template<class U> (3) (library fundamentals TS v2)
constexpr propagate_const& operator=( U&& u );
propagate_const& operator=( const propagate_const& ) = delete; (4) (library fundamentals TS v2)


Let t_ designate the private data member that is the wrapped pointer-like object.
1) Explicitly defaulted move assignment operator that move assigns this->t_ from p.t_.
2) Assigns std::move(pu.t_) to this->t_.
This function does not participate in overload resolution unless U is implicitly convertible to T.
3) Assigns std::forward<U>(u) to this->t_.
This function does not participate in overload resolution unless U is implicitly convertible to T and std::decay_t<U> is not a specialization of propagate_const
4) Copy assignment operator is explicitly deleted.

Parameters


p - another propagate_const object to move from
pu - another propagate_const object of a different specialization to move from
u - another object to assign to the contained pointer

Return value


*this.