std::experimental::ranges::StrictTotallyOrdered, (3) - Linux Man Pages

std::experimental::ranges::StrictTotallyOrdered,: std::experimental::ranges::StrictTotallyOrdered,

NAME

std::experimental::ranges::StrictTotallyOrdered, - std::experimental::ranges::StrictTotallyOrdered,

Synopsis


Defined in header <experimental/ranges/concepts>
template <class T>


concept bool StrictTotallyOrdered =
EqualityComparable<T> &&
requires(const std::remove_reference_t<T>& a,
const std::remove_reference_t<T>& b)           (1) (ranges TS)
-> Boolean&&;
-> Boolean&&;
<= -> Boolean&&;
>= -> Boolean&&;


};
template <class T, class U>


concept bool StrictTotallyOrderedWith =
StrictTotallyOrdered<T> &&
StrictTotallyOrdered<U> &&
CommonReference<
const std::remove_reference_t<T>&,
const std::remove_reference_t<U>&> &&
StrictTotallyOrdered<
ranges::common_reference_t<
const std::remove_reference_t<T>&,
const std::remove_reference_t<U>&>> &&
EqualityComparableWith<T, U> &&                  (2) (ranges TS)
requires(const std::remove_reference_t<T>& t,
const std::remove_reference_t<U>& u) {
-> Boolean&&;
-> Boolean&&;
<= -> Boolean&&;
>= -> Boolean&&;
-> Boolean&&;
-> Boolean&&;
<= -> Boolean&&;
>= -> Boolean&&;


};


1) The concept StrictTotallyOrdered<T> specifies that the comparison operators
==,!=,<,>,<=,>= on T yield results consistent with a strict total order on T.


StrictTotallyOrdered<T> is satisfied only if, given lvalues a, b and c of type const
std::remove_reference_t<T>:


  Exactly one of bool(a b), bool(a b) and bool(a == b) is true;
  If bool(a b) and bool(b c) are both true, then bool(a c) is true;
  bool(a b) == bool(b a)
  bool(a >= b) == !bool(a b)
  bool(a <= b) == !bool(b a)


2) The concept StrictTotallyOrderedWith<T, U> specifies that the comparison
operators ==,!=,<,>,<=,>= on (possibly mixed) T and U operands yield results
consistent with a strict total order. Comparing mixed operands yields results
equivalent to comparing the operands converted to their common type.


Formally, StrictTotallyOrderedWith<T, U> is satisfied only if, given any lvalue t of
type const std::remove_reference_t<T> and any lvalue u of type const
std::remove_reference_t<U>, and let C be ranges::common_reference_t<const
std::remove_reference_t<T>&, const std::remove_reference_t<U>&> :


  bool(t u) == bool(C(t) C(u))
  bool(t u) == bool(C(t) C(u))
  bool(t <= u) == bool(C(t) <= C(u))
  bool(t >= u) == bool(C(t) >= C(u))
  bool(u t) == bool(C(u) C(t))
  bool(u t) == bool(C(u) C(t))
  bool(u <= t) == bool(C(u) <= C(t))
  bool(u >= t) == bool(C(u) >= C(t))


  Equality preservation


An expression is equality preserving if it results in equal outputs given equal
inputs.


  The inputs to an expression consist of its operands.
  The outputs of an expression consist of its result and all operands modified by
 the expression (if any).


Every expression required to be equality preserving is further required to be
stable: two evaluations of such an expression with the same input objects must have
equal outputs absent any explicit intervening modification of those input objects.


Unless noted otherwise, every expression used in a requires-expression is required
to be equality preserving and stable, and the evaluation of the expression may only
modify its non-constant operands. Operands that are constant must not be modified.


  Implicit expression variations


A requires-expression that uses an expression that is non-modifying for some
constant lvalue operand also implicitly requires additional variations of that
expression that accept a non-constant lvalue or (possibly constant) rvalue for the
given operand unless such an expression variation is explicitly required with
differing semantics. These implicit expression variations must meet the same
semantic requirements of the declared expression. The extent to which an
implementation validates the syntax of the variations is unspecified.