std::filesystem::path::root_directory (3) - Linux Man Pages

std::filesystem::path::root_directory: std::filesystem::path::root_directory

NAME

std::filesystem::path::root_directory - std::filesystem::path::root_directory

Synopsis


path root_directory() const; (since C++17)


Returns the root directory of the generic-format path. If the path (in generic format) does not include root directory, returns path().

Parameters


(none)

Return value


The root directory of the path.

Exceptions


(none)

Example


// Run this code


  #include <iostream>
  #include <filesystem>
  namespace fs = std::filesystem;


  int main()
  {
      fs::path p = fs::current_path();


      std::cout << "The current path " << p << " decomposes into:\n"
                << "root name " << p.root_name() << '\n'
                << "root directory " << p.root_directory() << '\n'
                << "relative path " << p.relative_path() << '\n';
  }

Possible output:


  The current path "C:\Users\abcdef\Local Settings\temp" decomposes into:
  root name "C:"
  root directory "\"
  relative path "Users\abcdef\Local Settings\temp"

See also


          returns the root-name of the path, if present
root_name (public member function)
          returns the root path of the path, if present
root_path (public member function)