std::literals::chrono_literals::operator""y (3) - Linux Man Pages

std::literals::chrono_literals::operator""y: std::literals::chrono_literals::operator""y


std::literals::chrono_literals::operator""y - std::literals::chrono_literals::operator""y


Defined in header <chrono>
constexpr std::chrono::year operator ""y(unsigned long long y) noexcept; (1) (since C++20)

Forms a std::chrono::year literal representing a year in the proleptic Gregorian calendar.


y - the year value

Return value

A std::chrono::year initialized from int(y). If y > 32767, the stored value is unspecified.

Possible implementation

  constexpr std::chrono::year operator ""y(unsigned long long y) noexcept
      return std::chrono::year(int(y));


This operator is declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to this operator can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.


 This section is incomplete
 Reason: no example

See also

              constructs a year
constructor (public member function of std::chrono::year)