std::partial_sum (3) - Linux Manuals

std::partial_sum: std::partial_sum

NAME

std::partial_sum - std::partial_sum

Synopsis

Defined in header <numeric>
template< class InputIt, class OutputIt > (1)
OutputIt partial_sum( InputIt first, InputIt last, OutputIt d_first );
template< class InputIt, class OutputIt, class BinaryOperation >
OutputIt partial_sum( InputIt first, InputIt last, OutputIt d_first, (2)
BinaryOperation op );

Computes the partial sums of the elements in the subranges of the range [first, last) and writes them to the range beginning at d_first. The first version uses operator+ to sum up the elements, the second version uses the given binary function op
, both applying std::move to their operands on the left hand side
(since C++20).
Equivalent operation:

  *(d_first) = *first;
  *(d_first+1) = *first + *(first+1);
  *(d_first+2) = *first + *(first+1) + *(first+2);
  *(d_first+3) = *first + *(first+1) + *(first+2) + *(first+3);
  ...

op must not have side effects. (until C++11)
op must not invalidate any iterators, including the end iterators, or modify any elements of the range involved. (since C++11)

Parameters

first, last - the range of elements to sum
d_first - the beginning of the destination range; may be equal to first
              binary operation function object that will be applied.
              The signature of the function should be equivalent to the following:
op - Ret fun(const Type1 &a, const Type2 &b);
              The signature does not need to have const &.
              The type Type1 must be such that an object of type iterator_traits<InputIt>::value_type can be implicitly converted to Type1. The type Type2 must be such that an object of type InputIt can be dereferenced and then implicitly converted to Type2. The type Ret must be such that an object of type iterator_traits<InputIt>::value_type can be assigned a value of type Ret.

Type requirements

-
InputIt must meet the requirements of LegacyInputIterator.
-
OutputIt must meet the requirements of LegacyOutputIterator.

Return value

Iterator to the element past the last element written.

Complexity

Exactly (last - first) - 1 applications of the binary operation

Possible implementation

First version

  template<class InputIt, class OutputIt>
  OutputIt partial_sum(InputIt first, InputIt last,
                       OutputIt d_first)
  {
      if (first == last) return d_first;

      typename std::iterator_traits<InputIt>::value_type sum = *first;
      *d_first = sum;

      while (++first != last) {
         sum = std::move(sum) + *first; // std::move since C++20
         *++d_first = sum;
      }
      return ++d_first;

      // or, since C++14:
      // return std::partial_sum(first, last, d_first, std::plus<>());
  }

Second version

  template<class InputIt, class OutputIt, class BinaryOperation>
  OutputIt partial_sum(InputIt first, InputIt last,
                       OutputIt d_first, BinaryOperation op)
  {
      if (first == last) return d_first;

      typename std::iterator_traits<InputIt>::value_type sum = *first;
      *d_first = sum;

      while (++first != last) {
         sum = op(std::move(sum), *first); // std::move since C++20
         *++d_first = sum;
      }
      return ++d_first;
  }

Example

// Run this code

  #include <numeric>
  #include <vector>
  #include <iostream>
  #include <iterator>
  #include <functional>

  int main()
  {
      std::vector<int> v = {2, 2, 2, 2, 2, 2, 2, 2, 2, 2}; // or std::vector<int>v(10, 2);

      std::cout << "The first 10 even numbers are: ";
      std::partial_sum(v.begin(), v.end(),
                       std::ostream_iterator<int>(std::cout, " "));
      std::cout << '\n';

      std::partial_sum(v.begin(), v.end(), v.begin(), std::multiplies<int>());
      std::cout << "The first 10 powers of 2 are: ";
      for (auto n : v) {
          std::cout << n << " ";
      }
      std::cout << '\n';
  }

Output:

  The first 10 even numbers are: 2 4 6 8 10 12 14 16 18 20
  The first 10 powers of 2 are: 2 4 8 16 32 64 128 256 512 1024