std::vector<T,Allocator>::pop_back (3) - Linux Manuals

std::vector<T,Allocator>::pop_back: std::vector<T,Allocator>::pop_back

NAME

std::vector<T,Allocator>::pop_back - std::vector<T,Allocator>::pop_back

Synopsis

void pop_back();

Removes the last element of the container.
Calling pop_back on an empty container is undefined.
No iterators or references except for back() and end() are invalidated.

Parameters

(none)

Return value

(none)

Complexity

Constant.

Exceptions

(none)

Example

// Run this code

  #include <vector>
  #include <iostream>

  template<typename T>
  void print(T const & xs)
  {
      std::cout << "[ ";
      for(auto const & x : xs) {
          std::cout << x << ' ';
      }
      std::cout << "]\n";
  }

  int main()
  {
      std::vector<int> numbers;

      print(numbers);

      numbers.push_back(5);
      numbers.push_back(3);
      numbers.push_back(4);

      print(numbers);

      numbers.pop_back();

      print(numbers);
  }

Output:

  [ ]
  [ 5 3 4 ]
  [ 5 3 ]