stzrqf (l) - Linux Manuals

stzrqf: routine i deprecated and has been replaced by routine STZRZF

Command to display stzrqf manual in Linux: $ man l stzrqf

NAME

STZRQF - routine i deprecated and has been replaced by routine STZRZF

SYNOPSIS

SUBROUTINE STZRQF(: M, N, A, LDA, TAU, INFO )
: INTEGER INFO, LDA, M, N
: REAL A( LDA, * ), TAU( * )

PURPOSE

This routine is deprecated and has been replaced by routine STZRZF. STZRQF reduces the M-by-N ( M<=N ) real upper trapezoidal matrix A to upper triangular form by means of orthogonal transformations. The upper trapezoidal matrix A is factored as

A = ( R 0 ) * Z,
where Z is an N-by-N orthogonal matrix and R is an M-by-M upper triangular matrix.

ARGUMENTS

M (input) INTEGER: The number of rows of the matrix A. M >= 0.
N (input) INTEGER: The number of columns of the matrix A. N >= M.
A (input/output) REAL array, dimension (LDA,N): On entry, the leading M-by-N upper trapezoidal part of the array A must contain the matrix to be factorized. On exit, the leading M-by-M upper triangular part of A contains the upper triangular matrix R, and elements M+1 to N of the first M rows of A, with the array TAU, represent the orthogonal matrix Z as a product of M elementary reflectors.
LDA (input) INTEGER: The leading dimension of the array A. LDA >= max(1,M).
TAU (output) REAL array, dimension (M): The scalar factors of the elementary reflectors.
INFO (output) INTEGER: = 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value

FURTHER DETAILS

The factorization is obtained by Householderaqs method. The kth transformation matrix, Z( k ), which is used to introduce zeros into the ( m - k + 1 )th row of A, is given in the form

Z( k ) = ( I     0   ),

      ( 0  T( k ) )
where

T( k ) = I - tau*u( k )*u( k )aq,   u( k ) = (   1    ),
                                         (   0    )
                                         ( z( k ) ) tau is a scalar and z( k ) is an ( n - m ) element vector. tau and z( k ) are chosen to annihilate the elements of the kth row of X.
The scalar tau is returned in the kth element of TAU and the vector u( k ) in the kth row of A, such that the elements of z( k ) are in a( k, m + 1 ), ..., a( k, n ). The elements of R are returned in the upper triangular part of A.
Z is given by

Z =  Z( 1 ) * Z( 2 ) * ... * Z( m ).