std::adjacent_difference (3) Linux Manual Page
std::adjacent_difference – std::adjacent_difference
Synopsis
Defined in header<numeric>
template <class InputIt, class OutputIt>
OutputIt adjacent_difference(InputIt first, InputIt last, (until C++ 20)
OutputIt d_first);
template <class InputIt, class OutputIt>
constexpr OutputIt adjacent_difference(InputIt first, InputIt last, (since C++ 20)
OutputIt d_first);
template <class ExecutionPolicy, class ForwardIt1, class ForwardIt2>
ForwardIt2 adjacent_difference(ExecutionPolicy &&policy, ForwardIt1 first, ForwardIt1 last, (2)(since C++ 17)
ForwardIt2 d_first);
(1)
template <class InputIt, class OutputIt, class BinaryOperation>
OutputIt adjacent_difference(InputIt first, InputIt last, (until C++ 20)
OutputIt d_first,
BinaryOperation op);
template <class InputIt, class OutputIt, class BinaryOperation>
constexpr OutputIt adjacent_difference(InputIt first, InputIt last, (3)(since C++ 20)
OutputIt d_first,
BinaryOperation op);
template <class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class BinaryOperation>
ForwardIt2 adjacent_difference(ExecutionPolicy &&policy, ForwardIt1 first, ForwardIt1 last, (4)(since C++ 17)
ForwardIt2 d_first,
BinaryOperation op);
Computes the differences between the second and the first of each adjacent pair of elements of the range [first, last) and writes them to the range beginning at d_first + 1. An unmodified copy of *first is written to *d_first.
1,3) First, creates an accumulator acc whose type is InputIt's value type, initializes it with *first, and assigns the result to *d_first. Then, for every iterator i in [first + 1, last) in order, creates an object val whose type is InputIt's value type, initializes it with *i, computes
val - acc
(until C++20)
val - std::move(acc)
(since C++20) (overload (1)) or
op(val, acc)
(until C++20)
op(val, std::move(acc))
(since C++20) (overload (3)), assigns the result to *(d_first + (i - first)), and move assigns from val to acc.
first may be equal to d_first.
2,4) Performs *d_first = *first;. For every d in [1, last - first - 1], assigns *(first + d) - *(first + d - 1) (overload (2)) or op(*(first + d), *(first + d - 1)) (overload (4)) to *(d_first + d). This is executed according to policy. This overload only participates in overload resolution if std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true.
The behavior is undefined if the input and output ranges overlap in any way.
Equivalent operation:
*(d_first) = *first;
*(d_first+1) = *(first+1) - *(first);
*(d_first+2) = *(first+2) - *(first+1);
*(d_first+3) = *(first+3) - *(first+2);
...
op must not have side effects. (until C++11)
op must not invalidate any iterators, including the end iterators, or modify any elements of the ranges involved. (since C++11)
Parameters
first, last – the range of elements
d_first – the beginning of the destination range
policy – the execution policy to use. See execution_policy for details.
op – Ret fun(const Type1 &a, const Type2 &b);
Type requirements
–
InputIt must meet the requirements of LegacyInputIterator. InputIt’s value type must be MoveAssignable and constructible from the type of *first
–
OutputIt must meet the requirements of LegacyOutputIterator. both acc (the accumulated value) and the result of
val – acc or op(val, acc)
(until C++20)
val – std::move(acc) or op(val, std::move(acc))
(since C++20) must be writable to OutputIt
–
ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator. The results of *first, *first – *first (for (2)) and op(*first, *first) (for (4)) must be writable to ForwardIt2.
Return value
Iterator to the element past the last element written.
Notes
If first == last, this function has no effect and will merely return d_first.
Complexity
Exactly (last – first) – 1 applications of the binary operation
Exceptions
The overloads with a template parameter named ExecutionPolicy report errors as follows:
* If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard_policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
* If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
First version
Second version
Example
// Run this code
#include <numeric>
#include <vector>
#include <array>
#include <iostream>
#include <functional>
#include <iterator>
int main()
{
// Default implementation - the difference b/w two adjacent items
std::vector v{2, 4, 6, 8, 10, 12, 14, 16, 18, 20};
std::adjacent_difference(v.begin(), v.end(), v.begin());
for (auto n : v)
std::cout << n << ' ';
std::cout << '\n';
// Fibonacci
std::array<int, 10> a{1};
adjacent_difference(begin(a), std::prev(end(a)), std::next(begin(a)), std::plus<>{});
copy(begin(a), end(a), std::ostream_iterator<int>{std::cout, " "});
}
Output:
See also
partial_sum (function template)
accumulate (function template)
