std::adjacent_find (3) Linux Manual Page
std::adjacent_find – std::adjacent_find
Synopsis
Defined in header <algorithm>
template< class ForwardIt > (until C++20)
ForwardIt adjacent_find( ForwardIt first, ForwardIt last );
template< class ForwardIt > (since C++20)
constexpr ForwardIt adjacent_find( ForwardIt first, ForwardIt last );
template< class ExecutionPolicy, class ForwardIt >
ForwardIt adjacent_find( ExecutionPolicy&& policy, (2) (since C++17)
ForwardIt first, ForwardIt last ); (1)
template< class ForwardIt, class BinaryPredicate> (until C++20)
ForwardIt adjacent_find( ForwardIt first, ForwardIt last, BinaryPredicate p );
template< class ForwardIt, class BinaryPredicate> (since C++20)
constexpr ForwardIt adjacent_find( ForwardIt first, ForwardIt last, BinaryPredicate p ); (3)
template< class ExecutionPolicy, class ForwardIt, class BinaryPredicate>
ForwardIt adjacent_find( ExecutionPolicy&& policy, (4) (since C++17)
ForwardIt first, ForwardIt last, BinaryPredicate p );
Searches the range [first, last) for two consecutive identical elements.
1) Elements are compared using operator==.
3) Elements are compared using the given binary predicate p.
2,4) Same as (1,3), but executed according to policy. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true
Parameters
first, last – the range of elements to examine
policy – the execution policy to use. See execution_policy for details.
p – While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value_category (thus, Type1 & is not allowed
Type requirements
–
ForwardIt must meet the requirements of LegacyForwardIterator.
Return value
an iterator to the first of the first pair of identical elements, that is, the first iterator it such that *it == *(it+1) for the first version or p(*it, *(it + 1)) != false for the second version.
If no such elements are found, last is returned
Complexity
1,3) Exactly min((result-first)+1, (last-first)-1) applications of the predicate where result is the return value.
2,4) O(last-first) applications of the corresponding predicate.
Exceptions
The overloads with a template parameter named ExecutionPolicy report errors as follows:
* If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the standard_policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
* If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
First version
Second version
Example
// Run this code
#include <algorithm>
#include <iostream>
#include <vector>
#include <functional>
int main()
{
std::vector<int> v1{0, 1, 2, 3, 40, 40, 41, 41, 5};
auto i1 = std::adjacent_find(v1.begin(), v1.end());
if (i1 == v1.end()) {
std::cout << "no matching adjacent elements\n";
} else {
std::cout << "the first adjacent pair of equal elements at: "
<< std::distance(v1.begin(), i1) << '\n';
}
auto i2 = std::adjacent_find(v1.begin(), v1.end(), std::greater<int>());
if (i2 == v1.end()) {
std::cout << "The entire vector is sorted in ascending order\n";
} else {
std::cout << "The last element in the non-decreasing subsequence is at: "
<< std::distance(v1.begin(), i2) << '\n';
}
}
Output:
See also
unique (function template)
