std::is_compound (3) Linux Manual Page
std::is_compound – std::is_compound
Synopsis
Defined in header<type_traits>
template <class T>
(since C++ 11)
struct is_compound;
If T is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value equal true. For any other type, value is false.
Template parameters
T – a type to check
Helper variable template
template< class T > (since C++17)
inline constexpr bool is_compound_v = is_compound<T>::value;
Inherited from std::integral_constant
Member constants
value true if T is a compound type , false otherwise
[static]
Member functions
operator bool (public member function)
operator() returns value
(C++14)
Member types
Type Definition
value_type bool
type std::integral_constant<bool, value>
Notes
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
Possible implementation
Example
// Run this code
#include <iostream>
#include <type_traits>
int main()
{
class cls
{
};
std::cout << (std::is_compound<cls>::value
? "T is compound"
: "T is not a compound")
<< '\n';
std::cout << (std::is_compound<int>::value
? "T is compound"
: "T is not a compound")
<< '\n';
}
Output:
See also
is_fundamental checks if a type is a fundamental type
(C++11)
is_scalar checks if a type is a scalar type
(C++11)
is_object checks if a type is an object type
(C++11)
is_array checks if a type is an array type
(C++11)
