std::is_const (3) Linux Manual Page
std::is_const – std::is_const
Synopsis
Defined in header<type_traits>
template <class T>
(since C++ 11)
struct is_const;
If T is a const-qualified type (that is, const, or const volatile), provides the member constant value equal true. For any other type, value is false.
Template parameters
T – a type to check
Helper variable template
template< class T > (since C++17)
inline constexpr bool is_const_v = is_const<T>::value;
Inherited from std::integral_constant
Member constants
value true if T is a const-qualified type , false otherwise
[static]
Member functions
operator bool (public member function)
operator() returns value
(C++14)
Member types
Type Definition
value_type bool
type std::integral_constant<bool, value>
Notes
If T is a reference type then is_const<T>::value is always false. The proper way to check a potentially-reference type for const-ness is to remove the reference: is_const<typename remove_reference<T>::type>.
Possible implementation
Example
// Run this code
#include <iostream>
#include <type_traits>
int main()
{
std::cout << std::boolalpha;
std::cout << std::is_const<int>::value << '\n'; // false
std::cout << std::is_const<const int>::value << '\n'; // true
std::cout << std::is_const<const int *>::value << '\n'; // false
std::cout << std::is_const<int *const>::value << '\n'; // true
std::cout << std::is_const<const int &>::value << '\n'; // false
std::cout << std::is_const<typename std::remove_reference<const int &>::type>::value << '\n'; // true
}
Output:
See also
is_volatile checks if a type is volatile-qualified
(C++11)
as_const obtains a reference to const to its argument
(C++17)
