std::chrono::month::operator+=,std::chrono::month::operator-= (3) Linux Manual Page

std::chrono::month::operator+=,std::chrono::month::operator-= – std::chrono::month::operator+=,std::chrono::month::operator-=

Synopsis

constexpr std::chrono::month &operator+=(const std::chrono::months &m) noexcept;
(1)(since C++ 20)

    constexpr std::chrono::month &
    operator+=(const std::chrono::months &m) noexcept; (2) (since C++20)
Adds or subtracts m.count() from the month value, reducing the result modulo 12 to an integer in the range [1, 12].

1) Performs *this = *this + m;

2) Performs *this = *this - m;

Return value

A reference to this month after modification.

Notes

After a call to one of these functions, ok() is always true if no overflow occurred during the operation.

Example

 This section is incomplete
 Reason: no example

See also

operator++ increments or decrements the month
operator++(int) (public member function)
operator–
operator–(int)
                performs arithmetic on months
operator+ (function)
operator-