std::chrono::year::operator+=,std::chrono::year::operator-= (3) Linux Manual Page

std::chrono::year::operator+=,std::chrono::year::operator-= – std::chrono::year::operator+=,std::chrono::year::operator-=

Synopsis

constexpr std::chrono::year &operator+=(const std::chrono::years &y) noexcept;
(1)(since C++ 20)

    constexpr std::chrono::year &
    operator-=(const std::chrono::years &y) noexcept; (2) (since C++20)
Adds or subtracts y.count() years from the year value.

1) Equivalent to *this = *this + y;

2) Equivalent to *this = *this - y;

Return value

A reference to this year after modification.

Notes

If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.

Example

 This section is incomplete
 Reason: no example

See also

operator++ increments or decrements the year
operator++(int) (public member function)
operator–
operator–(int)
                performs arithmetic on years
operator+ (public member function)
operator-