std::disjunction (3) Linux Manual Page
std::disjunction – std::disjunction
Synopsis
Defined in header<type_traits>
template <class... B>
(1)(since C++ 17)
struct disjunction;
Forms the logical_disjunction of the type traits B…, effectively performing a logical OR on the sequence of traits.
The specialization std::disjunction<B1, …, BN> has a public and unambiguous base that is
* if sizeof…(B) == 0, std::false_type; otherwise
* the first type Bi in B1, …, BN for which bool(Bi::value) == true, or BN if there is no such type.
The member names of the base class, other than disjunction and operator=, are not hidden and are unambiguously available in disjunction.
Disjunction is short-circuiting: if there is a template type argument Bi with bool(Bi::value) != false, then instantiating disjunction<B1, …, BN>::value does not require the instantiation of Bj::value for j > i
Template parameters
B… – every template argument Bi for which Bi::value is instantiated must be usable as a base class and define member value that is convertible to bool
Helper variable template
template<class… B> (since C++17)
inline constexpr bool disjunction_v = disjunction<B…>::value;
Possible implementation
Notes
A specialization of disjunction does not necessarily inherit from of either std::true_type or std::false_type: it simply inherits from the first B whose ::value, explicitly converted to bool, is true, or from the very last B when all of them convert to false. For example, std::disjunction<std::integral_constant<int, 2>, std::integral_constant<int, 4>>::value is 2.
The short-circuit instantiation differentiates disjunction from fold expressions: a fold expression like (… || Bs::value) instantiates every B in Bs, while std::disjunction_v<Bs…> stops instantiation once the value can be determined. This is particularly useful if the later type is expensive to instantiate or can cause a hard error when instantiated with the wrong type.
Example
// Run this code
#include <type_traits>
#include <string>
// checking if Foo is constructible from double will cause a hard error
struct Foo {
template <class T>
struct sfinae_unfriendly_check {
static_assert(!std::is_same_v<T, double>);
};
template <class T>
Foo(T, sfinae_unfriendly_check<T> = {});
};
template <class... Ts>
struct first_constructible {
template <class T, class... Args>
struct is_constructible_x : std::is_constructible<T, Args...> {
using type = T;
};
struct fallback {
static constexpr bool value = true;
using type = void; // type to return if nothing is found
};
template <class... Args>
using with = typename std::disjunction<is_constructible_x<Ts, Args...>...,
fallback>::type;
};
// OK, is_constructible<Foo, double> not instantiated
static_assert(std::is_same_v<first_constructible<std::string, int, Foo>::with<double>,
int>);
static_assert(std::is_same_v<first_constructible<std::string, int>::with<>, std::string>);
static_assert(std::is_same_v<first_constructible<std::string, int>::with<const char *>,
std::string>);
static_assert(std::is_same_v<first_constructible<std::string, int>::with<void *>, void>);
int main()
{
}
See also
negation logical NOT metafunction
(C++17)
conjunction variadic logical AND metafunction
(C++17)
