std::experimental::conjunction (3) Linux Manual Page
std::experimental::conjunction – std::experimental::conjunction
Synopsis
Defined in header<experimental / type_traits>
template <class... B>
(library fundamentals TS v2)
struct conjunction;
Forms the logical_conjunction of the type traits B…, effectively performing a logical AND on the sequence of traits.
The specialization std::experimental::conjunction<B1, …, BN> has a public and unambiguous base that is
* if sizeof…(B) == 0, std::true_type; otherwise
* the first type Bi in B1, …, BN for which bool(Bi::value) == false, or BN if there is no such type.
The member names of the base class, other than conjunction and operator=, are not hidden and are unambiguously available in conjunction.
Conjunction is short-circuiting: if there is a template type argument Bi with bool(Bi::value) == false, then instantiating conjunction<B1, …, BN>::value does not require the instantiation of Bj::value for j > i.
Template parameters
B… – every template argument Bi for which Bi::value is instantiated must be usable as a base class and define member value that is convertible to bool
Helper variable template
template<class… B> (library fundamentals TS v2)
constexpr bool conjunction_v = conjunction<B…>::value;
Possible implementation
Notes
A specialization of conjunction does not necessarily inherit from either std::true_type or std::false_type: it simply inherits from the first B whose ::value, converted to bool, is false, or from the very last B when all of them convert to true. For example, conjunction<std::integral_constant<int, 2>, std::integral_constant<int, 4>>::value is 4.
Example
// Run this code
// func is enabled if all Ts... have the same type
template <typename T, typename... Ts>
std::enable_if_t<std::experimental::conjunction_v<std::is_same<T, Ts>...>>
func(T, Ts...)
{
// TODO something to show
}
See also
conjunction variadic logical AND metafunction
(C++17)
