std::experimental::propagate_const::operator= (3) Linux Manual Page

std::experimental::propagate_const<T>::operator= – std::experimental::propagate_const<T>::operator=

Synopsis

constexpr propagate_const &operator=(propagate_const &&p) = default;
(1)(library fundamentals TS v2)

    template <class U>
    (2)(library fundamentals TS v2)

        constexpr propagate_const &
        operator=(propagate_const<U> &&pu);

template <class U>
(3)(library fundamentals TS v2)

    constexpr propagate_const &
    operator=(U &&u);

propagate_const &operator=(const propagate_const &) = delete;
(4)(library fundamentals TS v2)

Let t_ designate the private data member that is the wrapped pointer-like object.
1) Explicitly defaulted move assignment operator that move assigns this->t_ from p.t_.
2) Assigns std::move(pu.t_) to this->t_.
This function does not participate in overload resolution unless U is implicitly convertible to T.
3) Assigns std::forward<U>(u) to this->t_.
This function does not participate in overload resolution unless U is implicitly convertible to T and std::decay_t<U> is not a specialization of propagate_const
4) Copy assignment operator is explicitly deleted.

Parameters

p – another propagate_const object to move from
pu – another propagate_const object of a different specialization to move from
u – another object to assign to the contained pointer

Return value

*this.