std::expm1,std::expm1f,std::expm1l (3) Linux Manual Page
std::expm1,std::expm1f,std::expm1l – std::expm1,std::expm1f,std::expm1l
Synopsis
Defined in header <cmath>
float expm1 ( float arg ); (1) (since C++11)
float expm1f( float arg );
double expm1 ( double arg ); (2) (since C++11)
long double expm1 ( long double arg ); (3) (since C++11)
long double expm1l( long double arg );
double expm1 ( IntegralType arg ); (4) (since C++11)
1-3) Computes the e (Euler’s number, 2.7182818) raised to the given power arg, minus 1.0. This function is more accurate than the expression std::exp(arg)-1.0 if arg is close to zero.
4) A set of overloads or a function template accepting an argument of any integral_type. Equivalent to 2) (the argument is cast to double).
Parameters
arg – value of floating-point or Integral_type
Return value
If no errors occur earg
-1 is returned.
If a range error due to overflow occurs, +HUGE_VAL, +HUGE_VALF, or +HUGE_VALL is returned.
If a range error occurs due to underflow, the correct result (after rounding) is returned.
Error handling
Errors are reported as specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
* If the argument is ±0, it is returned, unmodified
* If the argument is -∞, -1 is returned
* If the argument is +∞, +∞ is returned
* If the argument is NaN, NaN is returned
Notes
The functions std::expm1 and std::log1p are useful for financial calculations, for example, when calculating small daily interest rates: (1+x)n
-1 can be expressed as std::expm1(n * std::log1p(x)). These functions also simplify writing accurate inverse hyperbolic functions.
For IEEE-compatible type double, overflow is guaranteed if 709.8 < arg
Example
// Run this code
#include <iostream>
#include <cmath>
#include <cerrno>
#include <cstring>
#include <cfenv>
#pragma STDC FENV_ACCESS ON
int main()
{
std::cout << "expm1(1) = " << std::expm1(1) << '\n'
<< "Interest earned in 2 days on on $100, compounded daily at 1%\n"
<< " on a 30/360 calendar = "
<< 100 * std::expm1(2 * std::log1p(0.01 / 360)) << '\n'
<< "exp(1e-16)-1 = " << std::exp(1e-16) - 1
<< ", but expm1(1e-16) = " << std::expm1(1e-16) << '\n';
// special values
std::cout << "expm1(-0) = " << std::expm1(-0.0) << '\n'
<< "expm1(-Inf) = " << std::expm1(-INFINITY) << '\n';
// error handling
errno = 0;
std::feclearexcept(FE_ALL_EXCEPT);
std::cout << "expm1(710) = " << std::expm1(710) << '\n';
if (errno == ERANGE)
std::cout << " errno == ERANGE: " << std::strerror(errno) << '\n';
if (std::fetestexcept(FE_OVERFLOW))
std::cout << " FE_OVERFLOW raised\n";
}
Possible output:
See also
exp
expf
expl returns e raised to the given power (ex)
(C++11)
(C++11)
exp2
exp2f
exp2l returns 2 raised to the given power (2x)
(C++11)
(C++11)
(C++11)
log1p
log1pf
log1pl natural logarithm (to base e) of 1 plus the given number (ln(1+x))
(C++11)
(C++11)
(C++11)
