How to get the one character’s next character in ASCII table in Bash?

How to get the one character’s next character in ASCII table in Bash? For example, if I have ‘a’ in variable i, how to get ‘b’?

First, we need to get the integer value for the character.

char='b'
charint=$(printf "%d" "'$char'")

Then, we increase the integer by one

let charint=$charint+1

Last, we can get the new character by converting the integer to the character

newchar=$(printf "x$(printf %x $charint)")

Here, we use the inner printf to convert the integer to hexadecimal value and the outer printf to print the character from its hexadecimal value.

The result is as follows.

$ echo $newchar
c