top-like tools on Linux for network
How to display the network usage by processes like top for CPU/mem on Linux?
The nethogs tool is my favorite:
nethogs – Net top tool grouping bandwidth per process
How to display the network usage by processes like top for CPU/mem on Linux?
The nethogs tool is my favorite:
nethogs – Net top tool grouping bandwidth per process
How to find and change a user’s UID on Linux? Find the UID of a user: id -u $USER_NAME Change a user’s UID: # usermod -u $NEW_UID $USER_NAME Read more: How to move all the files under Users for a user to another drive on Windows? How to allow non-root users on Linux to mount…
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When should the authors anonymize themselves in a paper submitted to a conference for review? Several general concepts: Peer review is the evaluation of work by one or more people of similar competence to the producers of the work (peers). — Wikipedia Single-blind describes experiments where information that could introduce bias or otherwise skew the…
How to detect whether Linux runs in UEFI or BIOS mode inside the Linux itself without needed to boot the the management console of the mother board? You can detect whether Linux runs in EFI mode by checking whether /sys/firmware/efi exist. In bash, you can test by [ -d /sys/firmware/efi/ ] This technique is used…
How to add header footer in directory listing in Apache (httpd)? In the web directory’s .htaccess file: Options +Indexes IndexOptions FancyIndexing VersionSort NameWidth=* HTMLTable Charset=UTF-8 HeaderName /header.html ReadmeName /footer.html IndexIgnore header.html footer.html .htaccess header.html and footer.html are under the website root directory (not the Linux root). Read more: .htaccess: How to disable directory listing? How…
readlink -m can get canonical file name by resolving every symlinks in every component of the given path recursively. In Python, the os.readlink() function does not do so. Any equivalent function in Python to the readlink -m command line? Specifically, it does: canonicalize by following every symlink in every component of the given name recursively,…